1=(13+3x^2)

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Solution for 1=(13+3x^2) equation: 



1=(13+3x^2)

We move all terms to the left:

1-((13+3x^2))=0



We calculate terms in parentheses: -((13+3x^2)), so:

(13+3x^2)

We get rid of parentheses

3x^2+13

Back to the equation:

-(3x^2+13)



We get rid of parentheses

-3x^2-13+1=0

We add all the numbers together, and all the variables

-3x^2-12=0

a = -3; b = 0; c = -12;
Δ = b2-4ac
Δ = 02-4·(-3)·(-12)
Δ = -144
Delta is less than zero, so there is no solution for the equation

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